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Hazardville, CT Historical Place of Birth and Citizenship Data

 

ACS 2010-2014 data

Total population: 4,863

 Hazardville, CT%ConnecticutU.S.
Native4,68396.30%, see rank86.35%86.93%
Born in the State of Residence2,65354.55%, see rank55.22%58.73%
Born in Different State1,86438.33%, see rank27.55%26.78%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
1663.41%, see rank3.58%1.42%
Foreign Born1803.70%, see rank13.65%13.07%
Foreign Born with U.S. Citizenship1092.24%, see rank6.56%5.99%
Foreign Born without U.S. Citizenship711.46%, see rank7.10%7.09%
Born In Europe571.17%, see rank3.66%1.53%
Born In Asia781.60%, see rank3.23%3.82%
Born In Africa00.00%, see rank0.55%0.55%
Born In Oceania180.37%, see rank0.04%0.07%
Born In Latin America270.56%, see rank5.74%6.83%
Born In Northern America00.00%, see rank0.43%0.26%

ACS 2008-2012 data

Total population: 4,725

 Hazardville, CT%ConnecticutU.S.
Native4,49595.13%, see rank86.51%87.13%
Born in the State of Residence2,33149.33%, see rank55.28%58.71%
Born in Different State2,05043.39%, see rank27.70%27.04%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
1142.41%, see rank3.54%1.38%
Foreign Born2304.87%, see rank13.49%12.87%
Foreign Born with U.S. Citizenship972.05%, see rank6.33%5.71%
Foreign Born without U.S. Citizenship1332.81%, see rank7.16%7.16%
Born In Europe691.46%, see rank3.78%1.56%
Born In Asia791.67%, see rank3.09%3.67%
Born In Africa00.00%, see rank0.52%0.51%
Born In Oceania140.30%, see rank0.04%0.07%
Born In Latin America410.87%, see rank5.60%6.79%
Born In Northern America270.57%, see rank0.46%0.26%

ACS 2006-2010 data

Total population: 4,796

 Hazardville, CT%ConnecticutU.S.
Native4,56795.23%, see rank86.77%87.28%
Born in the State of Residence2,50452.21%, see rank55.31%58.66%
Born in Different State2,00141.72%, see rank28.07%27.28%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
621.29%, see rank3.39%1.33%
Foreign Born2294.77%, see rank13.23%12.72%
Foreign Born with U.S. Citizenship1012.11%, see rank6.14%5.48%
Foreign Born without U.S. Citizenship1282.67%, see rank7.09%7.24%
Born In Europe871.81%, see rank3.90%1.59%
Born In Asia751.56%, see rank2.89%3.54%
Born In Africa00.00%, see rank0.48%0.48%
Born In Oceania130.27%, see rank0.04%0.07%
Born In Latin America240.50%, see rank5.42%6.77%
Born In Northern America300.63%, see rank0.51%0.27%

ACS 2005-2009 data

Total population: 4,996

 Hazardville, CT%ConnecticutU.S.
Native4,83396.74%, see rank87.23%87.61%
Born in the State of Residence2,78955.82%, see rank55.88%58.98%
Born in Different State1,98139.65%, see rank28.19%27.35%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
631.26%, see rank3.17%1.29%
Foreign Born1633.26%, see rank12.77%12.39%
Foreign Born with U.S. Citizenship881.76%, see rank5.96%5.28%
Foreign Born without U.S. Citizenship751.50%, see rank6.81%7.11%
Born In Europe821.64%, see rank3.92%1.64%
Born In Asia150.30%, see rank2.70%3.34%
Born In Africa00.00%, see rank0.46%0.46%
Born In Oceania00.00%, see rank0.04%0.07%
Born In Latin America240.48%, see rank5.13%6.60%
Born In Northern America420.84%, see rank0.52%0.28%

US Census 2000 data

Total population: 4,900

 Hazardville, CT%ConnecticutU.S.
Native4,77597.45%, see rank89.14%88.95%
Born in the State of Residence2,78656.86%, see rank56.98%59.96%
Born in Different State1,93239.43%, see rank28.82%27.74%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
571.16%, see rank3.33%1.25%
Foreign Born961.96%, see rank10.86%11.05%
Foreign Born with U.S. Citizenship681.39%, see rank5.29%4.46%
Foreign Born without U.S. Citizenship280.57%, see rank5.57%6.60%
Born In Europe470.96%, see rank4.14%1.75%
Born In Asia00.00%, see rank2.06%2.92%
Born In Africa00.00%, see rank0.29%0.31%
Born In Oceania00.00%, see rank0.04%0.06%
Born In Latin America150.31%, see rank3.77%5.72%
Born In Northern America340.69%, see rank0.57%0.29%

* ACS stands for U.S. Census American Community Survey. According to the U.S. Census, if the date is a range, you can interpret the data as an average of the period of time.


 
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